Removing the Depth Dependence: Difference between revisions

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We are considering the [[Frequency Domain Problem]] for linear wave waves.
We are considering the [[Frequency Domain Problem]] for linear wave waves.  
If we have a problem in which the water depth is of constant depth <math>z=-h </math> (we are assuming
{{fixed body finite depth equations in two dimensions}}
the free surface is at <math>z=0</math>) and all the scatterers are of constant cross sections and
 
extend throughout the depth then we can remove the depth dependence by assuming
If we have a problem in which all the scatterers are of constant cross sections so
that
<center>
<math>\partial\Omega = \partial\hat{\Omega} \times z\in[-h,0]
</math>
</center>
where <math>\partial\hat{\Omega} </math> is a function only of <math>x,y</math>
i.e. the boundary of the scattering bodies is uniform with respect to depth.
Then we can remove the depth dependence by assuming
that the dependence on depth is given by  
that the dependence on depth is given by  
<center>
<center>

Revision as of 08:54, 23 August 2008

We are considering the Frequency Domain Problem for linear wave waves. The Standard Linear Wave Scattering Problem in Finite Depth for a fixed body is

[math]\displaystyle{ \begin{align} \Delta\phi &=0, &-h\lt z\lt 0,\,\,\mathbf{x} \in \Omega \\ \partial_z\phi &= 0, &z=-h, \\ \partial_z \phi &= \alpha \phi, &z=0,\,\,\mathbf{x} \in \partial \Omega_{\mathrm{F}}, \end{align} }[/math]


(note that the last expression can be obtained from combining the expressions:

[math]\displaystyle{ \begin{align} \partial_z \phi &= -\mathrm{i} \omega \zeta, &z=0,\,\,\mathbf{x} \in \partial \Omega_{\mathrm{F}}, \\ \mathrm{i} \omega \phi &= g\zeta, &z=0,\,\,\mathbf{x} \in \partial \Omega_{\mathrm{F}}, \end{align} }[/math]

where [math]\displaystyle{ \alpha = \omega^2/g \, }[/math]) The body boundary condition for a rigid body is just

[math]\displaystyle{ \partial_{n}\phi=0,\ \ \mathbf{x}\in\partial\Omega_{\mathrm{B}}, }[/math]

The equation is subject to some radiation conditions at infinity. We assume the following. [math]\displaystyle{ \phi^{\mathrm{I}}\, }[/math] is a plane wave travelling in the [math]\displaystyle{ x }[/math] direction,

[math]\displaystyle{ \phi^{\mathrm{I}}(x,z)=A \phi_0(z) e^{\mathrm{i} k x} \, }[/math]

where [math]\displaystyle{ A }[/math] is the wave amplitude (in potential) [math]\displaystyle{ \mathrm{i} k }[/math] is the positive imaginary solution of the Dispersion Relation for a Free Surface (note we are assuming that the time dependence is of the form [math]\displaystyle{ \exp(-\mathrm{i}\omega t) }[/math]) and

[math]\displaystyle{ \phi_0(z) =\frac{\cosh k(z+h)}{\cosh k h} }[/math]

In two-dimensions the Sommerfeld Radiation Condition is

[math]\displaystyle{ \left( \frac{\partial}{\partial|x|} - \mathrm{i} k \right) (\phi-\phi^{\mathrm{{I}}})=0,\;\mathrm{{as\;}}|x|\rightarrow\infty\mathrm{.} }[/math]

where [math]\displaystyle{ \phi^{\mathrm{{I}}} }[/math] is the incident potential.

If we have a problem in which all the scatterers are of constant cross sections so that

[math]\displaystyle{ \partial\Omega = \partial\hat{\Omega} \times z\in[-h,0] }[/math]

where [math]\displaystyle{ \partial\hat{\Omega} }[/math] is a function only of [math]\displaystyle{ x,y }[/math] i.e. the boundary of the scattering bodies is uniform with respect to depth. Then we can remove the depth dependence by assuming that the dependence on depth is given by

[math]\displaystyle{ \Phi(x,y,z) = \frac{\cosh \big( k (z+h) \big)}{\cosh(k h)} \phi(x,y) }[/math]

where [math]\displaystyle{ k }[/math] is the positive root of the Dispersion Relation for a Free Surface. Since [math]\displaystyle{ \Phi }[/math] satisfies Laplace's Equation, then [math]\displaystyle{ \phi }[/math] satisfies Helmholtz's Equation

[math]\displaystyle{ \nabla^2 \phi - k^2 \phi = 0 }[/math]

in the region not occupied by the scatterers.